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Fix(StoreMapper): Fix get wrong tools

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Fix unable to get tools after creating a new version bug
This commit is contained in:
Fat Snake
2024-04-26 16:55:35 +08:00
parent bc8b0b8f9f
commit 96afb185e7
1 changed files with 4 additions and 4 deletions
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8
src/main/resources/mapper/tool/StoreMapper.xml
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@@ -8,12 +8,12 @@
from (select *, row_number() over (partition by t_b_tool_main.tool_id, t_b_tool_main.author_id order by t_b_tool_main.id desc) as rn1 from (select *, row_number() over (partition by t_b_tool_main.tool_id, t_b_tool_main.author_id order by t_b_tool_main.id desc) as rn1
from t_b_tool_main from t_b_tool_main
where t_b_tool_main.deleted = 0 where t_b_tool_main.deleted = 0
and t_b_tool_main.publish != 0 and t_b_tool_main.review = 'PASS'
) as temp0 ) as temp0
where temp0.rn1 = 1 where temp0.rn1 = 1
) as temp1 ) as temp1
left join json_table(json_extract(temp1.keywords, '$[*]'), '$[*]' columns (keyword varchar(50) path '$')) as tk on true left join json_table(json_extract(temp1.keywords, '$[*]'), '$[*]' columns (keyword varchar(50) path '$')) as tk on true
<where> <where>
and temp1.publish != 0 and temp1.review = 'PASS'
<if test="searchValue != null"> <if test="searchValue != null">
and ( and (
temp1.name like concat('%', #{searchValue}, '%') temp1.name like concat('%', #{searchValue}, '%')
@@ -45,13 +45,13 @@
from (select *, row_number() over (partition by t_b_tool_main.tool_id, t_b_tool_main.author_id order by t_b_tool_main.id desc) as rn1 from (select *, row_number() over (partition by t_b_tool_main.tool_id, t_b_tool_main.author_id order by t_b_tool_main.id desc) as rn1
from t_b_tool_main from t_b_tool_main
where t_b_tool_main.deleted = 0 where t_b_tool_main.deleted = 0
and t_b_tool_main.publish != 0
and t_b_tool_main.review = 'PASS'
) as temp0 ) as temp0
where temp0.rn1 = 1 where temp0.rn1 = 1
) as temp1 ) as temp1
left join (select * from t_s_user where deleted = 0) as tsu on tsu.id = temp1.author_id left join (select * from t_s_user where deleted = 0) as tsu on tsu.id = temp1.author_id
where temp1.publish != 0 where tsu.username = #{username}
and temp1.review = 'PASS'
and tsu.username = #{username}
order by temp1.publish desc order by temp1.publish desc
) as temp2 ) as temp2
where temp2.rn2 = 1 where temp2.rn2 = 1